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  • arw

    Member
    July 9, 2020 at 12:13 pm

    What % win is needed to break-even when our opponent calls only 25% of the time?

    Fold EV + Call EV = 0

    Fold EV

    = (0.75)(300)

    Call EV

    = (0.25)[(W)(925) + (L)(-625)] where L = 1 – W

    = (0.25)[(W)(925) – (1 – W)(625)]

    = (0.25)[(W)(925) – (625 – 625W)

    = (0.25)(925W + 625W – 625)

    = (0.25)(1550W – 625)

    Total EV

    (0.75)(300) + (0.25)(1550W – 625) = 0

    225 + 387.5W – 156.25 = 0

    387.5W = 68.75

    W = 0.1774 or 17.7% win is needed


    When they fold more often, we need to win less often.